6.339x-4.9x^2=0

Solution for 6.339x-4.9x^2=0 equation:

6.339x-4.9x^2=0

a = -4.9; b = 6.339; c = 0;
Δ = b2-4ac
Δ = 6.3392-4·(-4.9)·0
Δ = 40.182921
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6.339)-\sqrt{40.182921}}{2*-4.9}=\frac{-6.339-\sqrt{40.182921}}{-9.8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6.339)+\sqrt{40.182921}}{2*-4.9}=\frac{-6.339+\sqrt{40.182921}}{-9.8}
$